Formula: 1 Mark
Steps: 1 Mark
Application: 1 Mark
Answer: 1 Marks
Given that,
The side of the square ABCD = 10 m.
Now the diameter of the circle will be equal to the side of the square ABCD = 10 m.
Area of the square = $a^2$
Area of the square is (10) $\times$ (10) = 100 $m^2$

Given diameter of circle = 10 m

Radius of the circle = $\frac{10}{2}$ = 5 m

Area of the circle 

= $\pi$ $\times$ ($r^2$)
= $\pi$ $\times$ ($5^2$)

= 78.5$m^2$   

Area of the triangle BDE

= $12$ $\times$ (BD) $\times$ (DE)

= 0.5 $\times$ (10) $\times$ (10)

= 50 $m^2$

Area of the shaded region

= Area of square ABCD - Area of circle + Area of triangle BDE

= 71.5 $m^2$
So, the area of the shaded region is 71.5 $m^2$.