Question
The value oflimx→01−cos3xxsin xcosx
Answer: Option C
:
C
limx→01−cos3xxsinxcosx=limx→0(1−cosx)(1+cosx+cos2x)xsinxcosx=limx→02sin2(x2)2sin(x2)cos(x2).x×(1+cosx+cos2x)cosx=limx→0sin(x2)2(x2)×1+cosx+cos2xcos(x2)cosx=12×3=32
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:
C
limx→01−cos3xxsinxcosx=limx→0(1−cosx)(1+cosx+cos2x)xsinxcosx=limx→02sin2(x2)2sin(x2)cos(x2).x×(1+cosx+cos2x)cosx=limx→0sin(x2)2(x2)×1+cosx+cos2xcos(x2)cosx=12×3=32
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