Question
limx→∞√x+sinxx−cosx=
Answer: Option B
:
B
limx→∞√x+sinxx−cosx
=limx→∞x12√1+sinxxx12√1−cosxx
We know, that for any value of x, sinx and cosx will be [-1,1]
So,=limx→∞Sinxx=0
And =limx→∞Cosxx=0
=x12√1+sinxx√1+sinxx√1+cosxx
=limx→∞11
=1
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:
B
limx→∞√x+sinxx−cosx
=limx→∞x12√1+sinxxx12√1−cosxx
We know, that for any value of x, sinx and cosx will be [-1,1]
So,=limx→∞Sinxx=0
And =limx→∞Cosxx=0
=x12√1+sinxx√1+sinxx√1+cosxx
=limx→∞11
=1
Was this answer helpful ?
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