Question
If f(x)={x2−3,2<x<32x+5,3<x<4, the equation whose roots are limx→3−f(x) and limx→3+f(x) is
Answer: Option C
:
C
f(x)={x2−3,2<x<32x+5,3<x<4
∴limx→3−f(x)=limx→3−(x2−3)=6
and limx→3+f(x)=limx→3+(2x+5)=11
Hence, the required equation will be
x2 - (sum of roots)x + (Products of roots) = 0
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:
C
f(x)={x2−3,2<x<32x+5,3<x<4
∴limx→3−f(x)=limx→3−(x2−3)=6
and limx→3+f(x)=limx→3+(2x+5)=11
Hence, the required equation will be
x2 - (sum of roots)x + (Products of roots) = 0
Was this answer helpful ?
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