Question
If G(x) = - √25−x2 then limx→1G(x)−G(1)x−1 has the value
Answer: Option D
:
D
limx→1−√25−x2−(−√24)x−1
=limx→1√24−√25−x2x−1×√24+√25−x2√24+√25−x2
limx→1x2−1(x−1)[√24+√25−x2]=22√24=12√6
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:
D
limx→1−√25−x2−(−√24)x−1
=limx→1√24−√25−x2x−1×√24+√25−x2√24+√25−x2
limx→1x2−1(x−1)[√24+√25−x2]=22√24=12√6
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