Question
limα→βsin2α−sin2βα2−β2 is equal to
Answer: Option B
:
B
limα→βsin2α−sin2βα2−β2=limα→βsin(α−β)sin(α+β)(α−β)(α+β)=sin2β(2β)
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:
B
limα→βsin2α−sin2βα2−β2=limα→βsin(α−β)sin(α+β)(α−β)(α+β)=sin2β(2β)
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