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Question
The number of real values of x for which the equality |3x2+12x+6|=5x+16 holds good is 
Options:
A .  4
B .  3
C .  2
D .  1
Answer: Option C
:
C
Equation|3x2+12x+6|=5x+16 ......(i)
when3x2+12x+60x2+4x2
|x+2|242|x+2|(2)2
⇔ x + 2≤ - 2 or x + 2≥2.......(ii)
Then (i) becomes 3x2+12x+6=5x+16
3x2+7x10=0⇒ x = 1, -103
But x = -103 does not satisfy (ii)
When 3x2+12x+6<0x2+4x>2
|x+2|222x2+2....(iii)
3x2+17x+22=0x=2,113
But x = - 113 does not satisfy (iii). So, 1 and -2 are the only solutions.

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