Question
x2−11x+a and x2−14x+2a will have a common factor, if a =
Answer: Option B
:
B
Exprssions are x2−11x+a and x2−14x+2a will have a common factor, then
⇒ x2−22a+14a=xa−2a=1−14+11
⇒ x2−8a=x−a=1−3⇒ x2=8a3andx=a3
⇒ (a3)2=8a3⇒ a29=8a3⇒ a = 0, 24.
Alternate Method : We can check by putting the values of a from the options.
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:
B
Exprssions are x2−11x+a and x2−14x+2a will have a common factor, then
⇒ x2−22a+14a=xa−2a=1−14+11
⇒ x2−8a=x−a=1−3⇒ x2=8a3andx=a3
⇒ (a3)2=8a3⇒ a29=8a3⇒ a = 0, 24.
Alternate Method : We can check by putting the values of a from the options.
Was this answer helpful ?
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