Question
If x is real, the expression x+22x2+3x+6 takes all value in the interval
Answer: Option B
:
B
If the given expression be y, then
y=2x2y+(3y−1)x+(6y−2)=0
If y≠ 0 then Δ≥ 0 for real x i.e. B2−4AC≥0
or −39y2+10y+1≥0or(13y+1)(3y−1)≤0
⇒ −113≤y≤13
if y = 0 then x = -2 which is real and this value of y is included in the above range.
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:
B
If the given expression be y, then
y=2x2y+(3y−1)x+(6y−2)=0
If y≠ 0 then Δ≥ 0 for real x i.e. B2−4AC≥0
or −39y2+10y+1≥0or(13y+1)(3y−1)≤0
⇒ −113≤y≤13
if y = 0 then x = -2 which is real and this value of y is included in the above range.
Was this answer helpful ?
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