Question
The roots of the equation √3x+1+1 = √x are
Answer: Option D
:
D
given equation is√3x+1+1 = √x
⇒√3x+1 = √x - 1
Squaring both the sides, we get 3x+ 1 = x + 1 -2√x
⇒2√x + 2x = 0 (irrational function)
Thusx≠ 0 andx≠ 1, Since equation is non-quadratic equation.
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:
D
given equation is√3x+1+1 = √x
⇒√3x+1 = √x - 1
Squaring both the sides, we get 3x+ 1 = x + 1 -2√x
⇒2√x + 2x = 0 (irrational function)
Thusx≠ 0 andx≠ 1, Since equation is non-quadratic equation.
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