Question
If x2−3x+2 be a factor of x4−px2+q, then (p, q) =
Answer: Option D
:
D
x2−3x+2 be factor of x4−px2+q=0
Hence (x2−3x+2)=0 ⇒ (x-2)(x-1) = 0
⇒ x = 2, 1, putting these values in given equation
so, 4p - q -16 = 0 ......(i)
and, p - q - 1 = 0 .......(ii)
Solving (i) and (ii), we get (p, q) = (5, 4)
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:
D
x2−3x+2 be factor of x4−px2+q=0
Hence (x2−3x+2)=0 ⇒ (x-2)(x-1) = 0
⇒ x = 2, 1, putting these values in given equation
so, 4p - q -16 = 0 ......(i)
and, p - q - 1 = 0 .......(ii)
Solving (i) and (ii), we get (p, q) = (5, 4)
Was this answer helpful ?
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