Question
If the sum of the first 14 terms of an AP is 1050 and its first term is 10, find the 20th term.
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Answer:
:
Here, S14= 1050, n = 14, a = 10.
As Sn= (n2) [2a + (n-1) d]
So,
1050=(142) [20 + 13d]
⇒1050=140+91d
⇒910=91d
⇒d=10
Therefore, a20=10+(20–1)×10=200
i.e. 20th term is 200.
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:
Here, S14= 1050, n = 14, a = 10.
As Sn= (n2) [2a + (n-1) d]
So,
1050=(142) [20 + 13d]
⇒1050=140+91d
⇒910=91d
⇒d=10
Therefore, a20=10+(20–1)×10=200
i.e. 20th term is 200.
Was this answer helpful ?
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