Question
Which term of the AP 3, 15, 27, 39, .... will be 132 more than its 54th term?
Answer: Option C
:
C
a=3
d=15−3=12
Let the required term be the nth term.
an=a+(n−1)d
a54+132=(32+53×12)+132
=32+636+132=800=an
800=32+(n−1)12
768=(n−1)12n−1=76812=64n=64+1=65
Thus, 65th term is 132 more than 54th term.
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:
C
a=3
d=15−3=12
Let the required term be the nth term.
an=a+(n−1)d
a54+132=(32+53×12)+132
=32+636+132=800=an
800=32+(n−1)12
768=(n−1)12n−1=76812=64n=64+1=65
Thus, 65th term is 132 more than 54th term.
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