Question
Find the difference between the sum of first 100 natural numbers and the sum of even numbers from 1 to 100.
Answer: Option C
:
C
Using the formula
Sn=n2[2n+(n−1)d]
Sum of first 100 natural numbers = 1002(2+99)=5050
Sum of even numbers from 1 to 100, there are 50 even numbers between 1 and 100.
So, we have
Sum of even numbers from 1 to 100 = 502(2×2+49×2) = 2550
Hence,the difference is 5050 - 2550 = 2500
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:
C
Using the formula
Sn=n2[2n+(n−1)d]
Sum of first 100 natural numbers = 1002(2+99)=5050
Sum of even numbers from 1 to 100, there are 50 even numbers between 1 and 100.
So, we have
Sum of even numbers from 1 to 100 = 502(2×2+49×2) = 2550
Hence,the difference is 5050 - 2550 = 2500
Was this answer helpful ?
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