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Question
 The sum of r terms of an AP is 2r2+3r. The nth​ term is ___.
Options:
A .  2n−1
B .  4n+1
C .  3n−1
D .  3n+1
Answer: Option B
:
B
Given, Sr=(2r2+3r), the sum upto r terms of an AP.
We know that the nth term of AP is
Tn=SnSn1.
Sn=2n2+3n and
Sn1=2(n1)2+3(n1).
Tn=SnSn1
=2n2+3n[2(n22n+1)+3n3]
=2n2+3n2n2+4n23n+3=4n+1

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