Question
Find the number of all natural numbers that lie between 24 and 101, which are divisible by 5.
Answer: Option B
:
B
Natural numbers that lie between 24 and 101,which are divisible by 5 are 25, 30,... and 100.
This is an A.P with first term a=25,common difference d=5 and the last term l=100.
But, l=a+(n−1)d.
⇒100=25+(n−1)×5
⇒75=(n−1)×5
⇒15=(n−1)
⇒16=n
Thus, there are 16 natural numbers between 24 and 101 that are divisible by 5.
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:
B
Natural numbers that lie between 24 and 101,which are divisible by 5 are 25, 30,... and 100.
This is an A.P with first term a=25,common difference d=5 and the last term l=100.
But, l=a+(n−1)d.
⇒100=25+(n−1)×5
⇒75=(n−1)×5
⇒15=(n−1)
⇒16=n
Thus, there are 16 natural numbers between 24 and 101 that are divisible by 5.
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