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Question
If one root of the equation ax2 + bx + c = 0 be n times the other root, then
Options:
A .  na2 = bc(n+1)2
B .  nb2 = ac(n+1)2
C .  nc2 = ab(n+1)2
D .  nb3 = ac(n+1)2
Answer: Option B
:
B
Let the roots be α and nα
Sum of roots,α + nα = -ba⇒α = -ba(n+1) ......(i)
and product,α.n.α = caα2 = cna ......(ii)
From (i) and (ii), we get
[ -ba(n+1) ]2 = cnab2a2(n+1)2 = cna
nb2 = ac(n+1)2.
Note : Students should remember this question as a fact.

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