Question
Dividing (a+b)2+(a−b)2 by (a2+b2) gives
___
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Answer:
:
(a+b)2+(a−b)2=(a2+b2+2ab)+(a2+b2−2ab)=2(a2+b2)
Dividing by a2+b2 we get,
= 2(a2+b2)(a2+b2)=2
Thus, ((a+b)2+(a−b)2)(a2+b2)=2
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:
(a+b)2+(a−b)2=(a2+b2+2ab)+(a2+b2−2ab)=2(a2+b2)
Dividing by a2+b2 we get,
= 2(a2+b2)(a2+b2)=2
Thus, ((a+b)2+(a−b)2)(a2+b2)=2
Was this answer helpful ?
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