Question
Factorise:4y2−12y+9
Answer: Option C
:
C
The given expression can be rewritten as,
(2y)2−2(2y)(3)+32.
Comparing with the identity
(a−b)2=a2−2ab+b2
we get,
(2y)2−2(2y)(3)+32
=(2y−3)2
=(2y−3)(2y−3)
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:
C
The given expression can be rewritten as,
(2y)2−2(2y)(3)+32.
Comparing with the identity
(a−b)2=a2−2ab+b2
we get,
(2y)2−2(2y)(3)+32
=(2y−3)2
=(2y−3)(2y−3)
Was this answer helpful ?
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