Question
Dividing x(3x2−27) by 3(x−3) gives x2+3x.
Answer: Option A
:
A
The given expression is
x(3x2−27)
Taking 3 common we get
= 3x(x2−9)
[Using a2−b2=(a+b)(a−b)]
= 3x(x+3)(x−3)
= 3x(x+3)(x−3)3(x−3)
= x(x+3)
= x2+3x
Hence, the given statement is true
Was this answer helpful ?
:
A
The given expression is
x(3x2−27)
Taking 3 common we get
= 3x(x2−9)
[Using a2−b2=(a+b)(a−b)]
= 3x(x+3)(x−3)
= 3x(x+3)(x−3)3(x−3)
= x(x+3)
= x2+3x
Hence, the given statement is true
Was this answer helpful ?
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