Question
A factor of a2−2ab+b2−c2 is ___________.
Answer: Option B
:
B
a2−2ab+b2−c2=(a−b)2–c2
Using identity x2−y2=(x+y)(x−y) we get
(a−b)2–c2 = [(a−b)+c][(a−b)−c]
Hence, factors ofa2−2ab+b2−c2 are a−b+c and a−b−c
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:
B
a2−2ab+b2−c2=(a−b)2–c2
Using identity x2−y2=(x+y)(x−y) we get
(a−b)2–c2 = [(a−b)+c][(a−b)−c]
Hence, factors ofa2−2ab+b2−c2 are a−b+c and a−b−c
Was this answer helpful ?
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