Question
Divide (a2+7a+10) by (a+5).
Answer: Option D
:
D
Given:a2+7a+10(a+5)...(i)
Comparing a2+7a+10 with the identity x2+(a+b)x+ab,
we note that,(a+b)=7andab=10
So,5+2=7and(5)(2)=10
Hence,
a2+7a+10
=a2+5a+2a+10
=a(a+5)+2(a+5)
=(a+2)(a+5)
From (i), we get
a2+7a+10(a+5)=(a+2)(a+5)(a+5)
=(a+2)
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:
D
Given:a2+7a+10(a+5)...(i)
Comparing a2+7a+10 with the identity x2+(a+b)x+ab,
we note that,(a+b)=7andab=10
So,5+2=7and(5)(2)=10
Hence,
a2+7a+10
=a2+5a+2a+10
=a(a+5)+2(a+5)
=(a+2)(a+5)
From (i), we get
a2+7a+10(a+5)=(a+2)(a+5)(a+5)
=(a+2)
Was this answer helpful ?
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