Question
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option B
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Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes \(\left(\frac{3}{2}\times60\right)\) = 90 days.
So, A takes 30 days to do the work.
A's 1 day's work = \(\frac{1}{30}\)
B's 1 day's work = \(\frac{1}{90}\)
(A + B)'s 1 day's work = \(\left(\frac{1}{30}+\frac{1}{90}\right)=\frac{4}{90}=\frac{2}{45}.\)
A and B together can do the work in \(\frac{45}{2}=22\frac{1}{2}days\)
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