Quantitative Aptitude
RACES AND GAMES MCQs
Races And Games Of Skill
Answer : Option D
Explanation :
While A runs 100 m, B runs (100-10)=90 m and C runs (100-13)=87 m
i.e., when B runs 90 m, C runs 87 m
$MF#%\text{=> when B runs 180 m, C runs }\dfrac{87}{90} \times 180 \text{= 174 m}$MF#%
Hence, in a 180 m race, B will beat C by (180-174)=6 m
Clearly, B covers 28 m in 7 seconds.
B's time over the course = (7/28 x 1000) sec = 250 seconds.
A's time over the course = (250 - 7) sec
= 243 sec = 4 min. 3 sec.
While A covers 1000 m, B covers (1000 - 40) m = 960 m
And C Covers (1000 - 64) m or 936 m
When B covers 960 m, C covers 936 m
When B cover 1000 m, C cover (936/960 x 1000) m =975
binduB can give C a start of (1000-975) or 25 m
Answer : Option D
Explanation :
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds.
Clearly, A beats B by (45-36)=9 seconds
$MF#%\text{Speed of B = }\dfrac{\text{Distance}}{\text{Time}} = \dfrac{100}{45}\text{ m/s}\\\\ \text{Distance Covered by B in 9 seconds = Speed × Time = }\dfrac{100}{45} \times 9\text{ = 20 metre}$MF#%
i.e., A beats B by 20 metre
Answer : Option B
Explanation :
When A covers 100 m, B covers (100-25)=75 m
When B covers 100 m, C covers (100-4)=96 m
$MF#%\text{=> When B covers 75 metre, C covers }\dfrac{96}{100}\times 75 = 72\text{ m}$MF#%
i.e., When A covers 100 m, B covers 75 m and C covers 72 m
=> In a 100 m race, A beat C by (100-72)=28 m