Answer: Option B. -> 10 points
$$\eqalign{
& A:B = 100:80 \cr
& A:C = 100:72 \cr
& \therefore \frac{B}{C} = {\frac{B}{A} \times \frac{A}{C}} = {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \cr
& = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr
& \therefore {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr} $$

Answer: Option B. -> 4.14 km/hr
A's speed = 5 km/hr = $$\left( {5 \times \frac{5}{{18}}} \right)$$  m/sec = $$\frac{25}{18}$$ m/sec
Time taken by A to cover 100 metres= $$\left( {100 \times \frac{{18}}{{25}}} \right)$$ = 72 sec
Time taken by B to cover 92 metres = (72 + 8) sec = 80 sec
B's speed
$$\frac{92}{80}$$ m/sec = $$\left( {\frac{{92}}{{80}} \times \frac{{18}}{5}} \right)$$  km/hr = $$\frac{414}{100}$$ km/hr= 4.14 km/hr

Answer: Option C. -> Rs. 66
End of
Suvarna
Tara
Uma
Vibha
4th Game
32
32
32
32
3rd Game
16
16
16
80
2nd Game
8
8
72
40
1st Game
4
68
36
20
OriginalMoney
62
34
18
10
Survarna starts with Rs. 66

Answer: Option C. -> 60%
Number of games played = 40
Number of won games = 24
Percentage of games played
= $$\left( {\frac{{24}}{{40}} \times 100} \right)$$ = 60%

Answer: Option D. -> 20 m
A : B : C = 1000 : (1000 - 50) : (1000 - 69)= 1000 : 950 : 931
In a 950 m race, B can give C a start of (950 - 931) m = 19 m
In a 1000 m race, B can give C a start of = $$\left( {\frac{{19}}{{950}} \times 1000} \right)$$ = 20 m

Answer: Option C. -> 8 m/sec, 7 m/sec
Suppose A covers 400 m in t seconds
Then, B covers 385 m in (t + 5) seconds
$$\eqalign{
& \therefore {\text{ B covers 400 m in}} \cr
& = \left\{ {\frac{{\left( {t + 5} \right)}}{{385}} \times 400} \right\}{\text{ sec}} \cr
& = \frac{{80\left( {t + 5} \right)}}{{77}}{\text{ sec}} \cr
& {\text{Also, B covers 400 m in}} \cr
& = \left( {t + 7\frac{1}{7}} \right){\text{ sec}} \cr
& = \frac{{\left( {7t + 50} \right)}}{7}{\text{ sec}} \cr
& \therefore \frac{{80\left( {t + 5} \right)}}{{77}} = \frac{{7t + 50}}{7} \cr
& \Rightarrow 80\left( {t + 5} \right) = 11\left( {7t + 50} \right) \cr
& \Rightarrow \left( {80t - 77t} \right) = \left( {550 - 400} \right) \cr
& \Rightarrow 3t = 150 \cr
& \Rightarrow t = 50 \cr
& \therefore {\text{ A's speed}} \cr
& = \frac{{400}}{{50}}\,m/\sec \cr
& = 8\,m/\sec \cr
& \therefore {\text{B's speed}} \cr
& = \frac{{385}}{{55}}\,m/\sec \cr
& = 7\,m/\sec \cr} $$

Answer: Option A. -> 200 m
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option B. -> 60
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option B. -> 80 sec
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!

Answer: Option B. -> 125m
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!