Quantitative Aptitude
RACES AND GAMES MCQs
Races And Games Of Skill
A's speed = `( 5 xx 5/18)` m/sec = `25/18` m/sec
Time taken by A to cover 100 m = `(100 xx 18/25)` sec = 72 sec.
`:.` Time taken by B to cover 95 m = ( 72 + 8) sec = 80 sec.
`:.` B's speed = `(92/80 xx 18/5)` kmph = 4.14 kmph
A : B = 200 : 169 and A : C = 200 : 182.
`C/B = (C/A xx A/B) = 182/200 xx 200/169) ` = 182 : 169
When C covers 182 m, B covers 169 m.
When C covers 350 m, B covers `(169/182 xx 350)`m = 325 m.
A : B = 100 : 90 and A : C = 100 : 87
`B/C = B/A xx A/C = 90/100 xx 100/87 = 30/29`
When B runs 30 m, C runs 29 m.
When B runs 180 m , C runs `(29/30 xx 180)`m = 174 m
`:.` B beats C by (180 - 174) m = 6 m.
A : B = 100 : 90 and A : C = 100 : 72
B : C = `B/A xx A/C` = `90/100 xx 100/72 = 90/72`
When B runs 90 m , C runs 72 m.
When B runs 100 m, C runs `(72/90 xx 100)`m = 80 m
`:.` B can give C 20 m.
A : B = 100 : 75 and B : C = 100 : 96.
`:.` A : C = `(A/B xx B/C) = ( 100/75 xx 100/96)`
= `100/72 = 100 : 72`
`:.` A beats C by (100 - 72)m = 28 m.
To reach the winning post A will have to cover a distance of(500 - 140) m i.e. 360 m.
while A cover 3 m., B cover 4 m.
while A covers 360 m , B cover `(4/3 xx 360)` m = = 480 m.
Thus when A reached the winning post , B covers 480 m and therefore remains 20 m. behind .
`:.` A wins by 20 m.
Ratio of the speeds of A and B = `5/3 : 1` = 5 : 3
Thus , in a race of 5 m , A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in a race of `(5/2 xx 80)` m = 200 m.
`:.` Winning post is 200 m away from the starting point
When it runs 25 m , A runs `45/2` m.
When B runs 1000 m. A runs `(45/2 xx 1/25 xx 1000)` m = 900 m.
`:.` B beats A by 100 m.
B runs `45/2` m in 6 sec.
`:.` B covers 300 m in `(6 xx 2/45 xx 300)`sec. = 80 sec.
B runs 35 m in 7 sec.
`:.` B covers 200 m in `(7/35 xx 200)) `sec = 40 sec.
B's time over the cours = 40 sec.
`:.` A's time over the course = (40 - 7) sec. = 33 sec.