B runs   m in 6 sec \(\frac{2}{45}\)

So, B covers 300 m in \(\left(6\times\frac{2}{45}\times300\right)sec=80sec.\)

Ratio of the speeds of A and B = \(\frac{5}{3}\) : 1 = 5 : 3.

Thus, in race of 5 m, A gains 2 m over B.

2 m are gained by A in a race of 5 m.

80 m will be gained by A in race of \(\left(\frac{5}{2}\times80\right)m=200m.\)

So, Winning post is 200 m away from the starting point.

A : B = 100 : 75

B : C = 100 : 96.

S0, A : C = \(\left(\frac{A}{B}\times\frac{B}{C}\right)=\left(\frac{100}{75}\times\frac{100}{96}\right)= \frac{100}{72}=100:72.\)

So, A beats C by (100 - 72) m = 28 m.