Question
A runs 1 \(\frac{2}{3}\) times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Answer: Option A
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Ratio of the speeds of A and B = \(\frac{5}{3}\) : 1 = 5 : 3.
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of \(\left(\frac{5}{2}\times80\right)m=200m.\)
So, Winning post is 200 m away from the starting point.
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