Sail E0 Webinar

10th Grade > Chemistry

PERIODIC CLASSIFICATION OF ELEMENTS MCQs

Total Questions : 54 | Page 3 of 6 pages
Question 21. Elements in the 16th group of the Modern Periodic Table are also called  ____.
  1.    metals
  2.    halogens
  3.    chalcogens
  4.    conductors
 Discuss Question
Answer: Option C. -> chalcogens
:
C
Elements in the 16th group of the modern periodic table are also known as chalcogens. The 16th group consists of the elements, oxygen (O), sulphur (S), selenium (Se), tellurium (Te), and the radioactive element polonium (Po). They are the family of oxygen and can be found in copper ores.
Question 22. Which element in the modern periodic table is similar to eka-silicon?
  1.    Phosphorus
  2.    Carbon
  3.    Germanium
  4.    Aluminium
 Discuss Question
Answer: Option C. -> Germanium
:
C
Mendeleev predicted the existence of few elements and left empty spaces in his periodic table. One such element whose existence he predicted was eka-silicon. In the modern periodic table, germanium has the properties similar to that of eka-silicon.
Question 23. Which element can be placed in the region marked by question mark ?
Which Element Can Be Placed In The Region Marked By Question...
  1.    Ga
  2.    Br
  3.    Si
  4.    I
 Discuss Question
Answer: Option D. -> I
:
D
Iodine is a lustrous non-metal.
Question 24. Which amongst the following elements has the largest atomic size?
  1.    Beryllium
  2.    Carbon
  3.    Oxygen
  4.    Fluorine
 Discuss Question
Answer: Option A. -> Beryllium
:
A
The atomic size of an atom is the distance between the nucleus and the outermost shell of an atom.Atomic size reduces across a period from left to right. Beryllium, carbon, oxygen and fluorine belongto second period. Since beryllium is placed at the leftmost side of the period, therefore ithas the largest atomic size.
Question 25.


Metallic character _________ down the group in the periodic table.


  1.     increases
  2.     decreases
  3.     increases and then decreases
  4.     decreases and then increases
 Discuss Question
Answer: Option A. -> increases
:
A

Metallic character is the tendency of an element to lose an electron easily. As we go down the group, the size of atoms increases.
Due to this, the nuclear force of attraction on the electrons in the outermost shell decreases, because of which they can be removed easily. Therefore, metallic character increases down the group.


Question 26.


No. of neutrons present in 23892Ur are: 


  1.     148
  2.     146
  3.     144
  4.     92
 Discuss Question
Answer: Option B. -> 146
:
B

Number of neutrons = Mass No. - Atomic No.
Since 238 is the mass number,
No. of neutrons = 238 - 92 = 146


Question 27.


Which of the following elements does not lose an electron easily? 


  1.     Na
  2.    
  3.     Mg
  4.     Al
 Discuss Question
Answer: Option B. ->
:
B

Elements try to attain the nearest noble gas configuration by losing or gaining electrons.
Fluorine has 7 electrons in its outer shell. These 7 electrons are bound tightly by the nucleus. It has a tendency to gain an electron to achieve the nearest noble gas configuration.
However, Na, Mg and Al tend to lose electrons to acheive the nearest noble gas configuration.


Question 28.


Noble gases are considered to be inert. Identify pairs of noble gases from the options:


  1.     Helium and hydrogen
  2.     Neon and argon
  3.     Helium and neon
  4.     Nitrogen and neon
 Discuss Question
Answer: Option B. -> Neon and argon
:
B and C

The term inert means that a substance is chemically non-reactive. Noble gases are considered to be inert. Helium, neon, argon, krypton, xenon and radon are the noble gases that are present in the 18th group of the periodic table.


Question 29.


Which of the following is a Dobereiner's triad?


  1.     Ne, Ca, Na
  2.     H2,N2,O2
  3.     Li, Na, K
  4.     Cl, Na, Ca
 Discuss Question
Answer: Option C. -> Li, Na, K
:
C

According to Dobereiner's law of triads, the atomic mass of the middle element of a triad is equal to the arithmetic mean of the atomic masses of the other two elements.
In the triad of lithium, sodium and potassium. The atomic mass of lithium is 7 and the atomic mass of potassium is 39. The arithmetic mean of atomic masses of lithium and potassium gives atomic mass of sodium i.e. 23.


Question 30.


Atomic mass of X and Z are 20 u and 40 u respectively. If X, Y and Z constitute Dobereiner’s triads, what should be the atomic mass of Y (in u)?


  1.     20
  2.     40
  3.     30
  4.     60
 Discuss Question
Answer: Option C. -> 30
:
C
According to Dobereiner's law of triads, the atomic mass of the middle element of the triad is equal to the arithmetic mean of the atomic masses of the other two elements.
Since, Y is the middle element of the triad, its mass should be the average of X and Z, that is,
Y=X+Z2=20+402=30 u

Latest Videos

Latest Test Papers