On any  number line, integers that are on the left side of a number are less than that integer.
All negative integers are on the left of  0 on a  number line. So zero should be greater than all negative integers. 
So, Statement 1 is false.

Positive integers lie on the right of  0 on a number line. So zero should be less than all positive integers. 
So, Statement 2 is also false.

For positive values, we move towards the right side of the zero and for negative values, we move towards the left side of the zero, on the number line. So for marking +3, which is a positive integer, we have to move 3 steps towards the right side of zero.

On a number line, all integers are marked at equal intervals.

All positive integers are greater than negative integers. So -5 is lesser than +5

A profit of Rs. 109 is represented as +Rs.109.
A loss of Rs. 901 is represented as -Rs.901.

The temperature 26${}^{\circ }$C above 0${}^{\circ }$C can be represented as +26${}^{\circ }$C and  the temperature 13${}^{\circ }$C  below 0${}^{\circ }$C can be represented as -13${}^{\circ }$C.

Integers comprise of all natural numbers and their negatives, including 0. All natural numbers, whole numbers and negative numbers are subsets of integers.

The only thing left was negative numbers, which is a part of Integers.

Integers include all natural numbers, their negatives and 0.

Solution: 1 Mark
$-13+(-69)+57-(-89)-(53+(-49\left)\right)$

$=-13-69+57+89-(53-49)$

$=-13-69+57+89-53+49$

First, take all ‘$-$’ terms and then take all ‘$+$’ terms and add them,

$=(-13-69-53)+(57+89+49)$

$=-135+195$

$=60$