6th Grade > Mathematics
INTEGERS MCQs
Total Questions : 99
| Page 3 of 10 pages
Answer: Option A. -> True
:
A
For positive values, we move towards theright side of the zeroand for negative values, we move towards the left side of the zero, on the number line. So for marking +3, which is a positive integer, we have to move3 steps towards the right side of zero.
:
A
For positive values, we move towards theright side of the zeroand for negative values, we move towards the left side of the zero, on the number line. So for marking +3, which is a positive integer, we have to move3 steps towards the right side of zero.
Answer: Option C. -> Both statements are false.
:
C
On any number line, integersthat are on the left side of a number are lessthan that integer.
All negative integers are on the left of0 on a number line. So zero should be greater than all negative integers.
So, Statement 1 is false.
Positive integers lie on the right of0 on a number line. So zero should be less than all positive integers.
So, Statement 2is also false.
:
C
On any number line, integersthat are on the left side of a number are lessthan that integer.
All negative integers are on the left of0 on a number line. So zero should be greater than all negative integers.
So, Statement 1 is false.
Positive integers lie on the right of0 on a number line. So zero should be less than all positive integers.
So, Statement 2is also false.
Answer: Option D. -> +Rs.109 and -Rs.901 respectively.
:
D
A profit of Rs. 109 is represented as +Rs.109.
Aloss of Rs. 901 is represented as -Rs.901.
:
D
A profit of Rs. 109 is represented as +Rs.109.
Aloss of Rs. 901 is represented as -Rs.901.
Question 25. Numbers are said to be in descending order when they are arranged from the largest to the smallest number. E.g. 25, 21, 17, 13 and 9 are arranged in descending order.
Write the following integers in descending order? [3 MARKS]
(a). 15, -14, 13, 12, 0
(b). 3, -3, 5, -5, 7
(c). 6, -7, -8, 9, -10
Write the following integers in descending order? [3 MARKS]
(a). 15, -14, 13, 12, 0
(b). 3, -3, 5, -5, 7
(c). 6, -7, -8, 9, -10
:
Each option: 1 Mark
(a). 15, 13, 12, 0, -14
⇒(15 is the largest and -14 is the smallest among the given integers)
(b). 7, 5, 3, -3, -5
⇒(7 is the largest and -5 is the smallest among the given integers)
(c). 9, 6, -7, -8, -10
⇒(9 is the largest and -10 is the smallest among the given integers)
:
Solution: 1 Mark
−13+(−69)+57−(−89)−(53+(−49))
=−13−69+57+89−(53−49)
=−13−69+57+89−53+49
First, take all ‘−’ terms and then take all ‘+’ terms and add them,
=(−13−69−53)+(57+89+49)
=−135+195
=60
:
Each option: 1 Mark
(a). 0
(b). −6+3=−3
(c). The opposite of −5 is +5
:
Each option: 1 Mark
(a). Largest = 175, Smallest = −365
(b). [(−3)+(−2)]+[(−5)+7]
⇒[−3−2]+[−5+7]
⇒[−5+2]=−3
(c).−6÷−3=−6−3=2
(⇒−÷−=+)
(d).3×6×2×(−40)
⇒18×2×(−40)
⇒36×(−40)=−1440
(⇒as+×−=−)
:
Each option: 1 Mark
(i) The predecessor of −2 is −3
because −3 is 1 less than −2
∴24−3=−8
(ii) The successor of −2 is −1
because −1 is 1 more than −2
∴−82−1=82
:
Steps: 1 Mark
Answer: 1 Mark
Sum of 17 and -5
⇒17+(−5)=17−5=12
Now, adding 3 and (-15)to 12
⇒12+3+(−15)=15+(−15)
⇒15−15=0