8th Grade > Mathematics
COMPARING QUANTITIES MCQs
Total Questions : 59
| Page 2 of 6 pages
Answer: Option A. -> 24
:
A
200% of 12
=200100×12=2×12=24
:
A
200% of 12
=200100×12=2×12=24
Answer: Option B. -> Selling Price
:
B
Goods and ServiceTax (GST) is levied on selling price.
:
B
Goods and ServiceTax (GST) is levied on selling price.
Answer: Option C. -> 3 hours ago
:
C
If there are 1000 bacteria now, 1 hour agothere would have been 500 since the number of bacteria doubles every hour. 2 hours ago there would have been half of 500 bacteria, that is 250 bacteria. 3 hours ago there would have been 125 bacteria.
:
C
If there are 1000 bacteria now, 1 hour agothere would have been 500 since the number of bacteria doubles every hour. 2 hours ago there would have been half of 500 bacteria, that is 250 bacteria. 3 hours ago there would have been 125 bacteria.
Answer: Option A. -> ₹ 4,93,125
:
A
Given that A =₹ 3,15,600 , r = 20 % ; n = 2 years.
Let P be the value of the car two years ago.
A=P(1−20100)2
315600=P(1−15)2
315600=P(4×45×5)
P=315600×5×54×4
P=₹4,93,125
∴Purchase value of the car=₹4,93,125
:
A
Given that A =₹ 3,15,600 , r = 20 % ; n = 2 years.
Let P be the value of the car two years ago.
A=P(1−20100)2
315600=P(1−15)2
315600=P(4×45×5)
P=315600×5×54×4
P=₹4,93,125
∴Purchase value of the car=₹4,93,125
Answer: Option B. -> Profit of ₹300
:
B
Profit on one of the bats = 10% of ₹ 6000
= 10100×6000= ₹600
Hence, the Selling price
= Cost price + Profit
= ₹ (6000 + 600) = ₹ 6600
Loss on the other bat
= 5% of ₹ 6000
= 5100×₹6000
= ₹ 300
Selling price = Cost price - Loss
= ₹ (6000 - 300)
= ₹ 5700
Total cost price (CP) = ₹ 12000
Total selling price (SP) =₹6600+₹5700 = ₹ 12,300
Hence, as SP > CP, he has made a profit of ₹ (12,300−12,000)=₹ 300.
:
B
Profit on one of the bats = 10% of ₹ 6000
= 10100×6000= ₹600
Hence, the Selling price
= Cost price + Profit
= ₹ (6000 + 600) = ₹ 6600
Loss on the other bat
= 5% of ₹ 6000
= 5100×₹6000
= ₹ 300
Selling price = Cost price - Loss
= ₹ (6000 - 300)
= ₹ 5700
Total cost price (CP) = ₹ 12000
Total selling price (SP) =₹6600+₹5700 = ₹ 12,300
Hence, as SP > CP, he has made a profit of ₹ (12,300−12,000)=₹ 300.
Answer: Option A. -> True
:
A
Fraction of apples =Number of applesTotal number of fruits in the bag
So, fraction of apples =1030=13
:
A
Fraction of apples =Number of applesTotal number of fruits in the bag
So, fraction of apples =1030=13
Answer: Option B. -> 46,20,000
:
B
The price hike is 10%. So, 10% of 42,00,000 would give you the price hike.
Hence, 10100×42,00,000=4,20,000
So, adding this amount to the previous price i.e. 42 lakhs would give you the new price.
So, 42,00,000 + 4,20,000 =₹ 46,20,000
:
B
The price hike is 10%. So, 10% of 42,00,000 would give you the price hike.
Hence, 10100×42,00,000=4,20,000
So, adding this amount to the previous price i.e. 42 lakhs would give you the new price.
So, 42,00,000 + 4,20,000 =₹ 46,20,000
Answer: Option A. -> ₹ 3120
:
A
GST is calculated on the selling price. Since the bill amount is the selling price, the GSTis added to the bill amount itself.
So, GST = 4% of₹ 3000
= 4100×3000
= ₹120
Final bill amount = ₹3000 + ₹120 =₹3120
:
A
GST is calculated on the selling price. Since the bill amount is the selling price, the GSTis added to the bill amount itself.
So, GST = 4% of₹ 3000
= 4100×3000
= ₹120
Final bill amount = ₹3000 + ₹120 =₹3120
Answer: Option A. -> ₹4000
:
A
When a principal is promised with an interest to be compounded annually, the amount after one year becomes the principal for the next year. So, 10100×400000=40,000
₹40,000 added to ₹4,00000 would be the new principal for the next year i.e. 4,40,000. The interest for the second year is calculated on the new principal amount: 10100×440000×1=44,000
So, the final amount after 2 years(compounded annually with 10% interest) = ₹440000 + 44000 = ₹4,84,000.
If the principal would have been deposited for an annual simple interest for 10% for a period of two years would be 10100×400000×2=80,000
Therefore amount = ₹4,00000 + ₹80,000 = ₹4,80,000.
So, compound interest is ₹4,000 more than a simple interest for a period of two years.
:
A
When a principal is promised with an interest to be compounded annually, the amount after one year becomes the principal for the next year. So, 10100×400000=40,000
₹40,000 added to ₹4,00000 would be the new principal for the next year i.e. 4,40,000. The interest for the second year is calculated on the new principal amount: 10100×440000×1=44,000
So, the final amount after 2 years(compounded annually with 10% interest) = ₹440000 + 44000 = ₹4,84,000.
If the principal would have been deposited for an annual simple interest for 10% for a period of two years would be 10100×400000×2=80,000
Therefore amount = ₹4,00000 + ₹80,000 = ₹4,80,000.
So, compound interest is ₹4,000 more than a simple interest for a period of two years.
Answer: Option D. -> ₹4921
:
D
Given that P =₹ 64,000 r= 5 % and n = 112 years
Since, the rate of interest is calculated annually , for 6 months it will be 2.5 %
A=P(1+r100)n
Here r = 52 % and n = 3 half years
A=64,000(1+52×100)3
A=64,000(4140)3
A=68921
∵ Compound interest = Amount - Principal
=68921 - 64000
=₹ 4921
:
D
Given that P =₹ 64,000 r= 5 % and n = 112 years
Since, the rate of interest is calculated annually , for 6 months it will be 2.5 %
A=P(1+r100)n
Here r = 52 % and n = 3 half years
A=64,000(1+52×100)3
A=64,000(4140)3
A=68921
∵ Compound interest = Amount - Principal
=68921 - 64000
=₹ 4921
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