Answer: Option B. -> 25%
:
B
As the selling price is less than the cost price, the owner incurred loss.
Loss = Difference in the amount for which it was purchased and the amount for which it was sold.
$\therefore \text{Loss}=₹80000-₹60000=₹20000$
$\text{Percentage of loss}=\frac{\text{loss}}{\text{cost price}}\times 100$
$=\frac{20000}{80000}\times 100=25\%$

Answer: Option B. -> ₹ 2,17,500
:
B
Depreciation means a decrease in the value due to use and age of the item.
$A=P\times {[1-\frac{r}{100}]}^n$, where $A$ is the amount, $P$ is the principal, $r$ is the rate of interest and $n$ is the time period.
So, priceat the end of one year $=2,50,000\times {[1-\frac{10}{100}]}^1$=₹2,25,000
Depreciation for next four months $=2,25,000\times 10\times \frac{1}{100\times 3}$ = ₹7500
So, the depreciated value afterone year and four months $=2,25,000-7,500$ = ₹2,17,500

Answer: Option A. -> Rs. 162
:
A
$8\%\text{of}150=\frac{8}{100}\times 150=Rs.12$
New price $=150+12=Rs.162$

Answer: Option A. -> ₹ 55625
:
A
Let the present value of the car be$V$ which is₹ 35600,
Time, $n=2$ years, and rate of interest,$r=20\%$
Let the purchase price be$V_0$
$\text{Using,}V=V_0{(1-\frac{r}{100})}^n$
$\Rightarrow 35600=V_0{(1-\frac{20}{100})}^2\Rightarrow 35600=V_0{\left(\frac{80}{100}\right)}^2=V_0\left(\frac{16}{25}\right)\Rightarrow V_0=35600\times \frac{25}{16}=₹55625$

Answer: Option D. -> 50
:
D
Let the strength of the class be $x$.
Given that $60\%$ are girls, so $40\%$ are boys.
Now,$40\%\times x=20$
(Since number of boys in the class is 20)
$\Rightarrow \frac{40}{100}\times x=20$
$\Rightarrow x=\frac{20\times 100}{40}$
$\Rightarrow x=50$
Therefore, total number of students in the class is 50.

Answer: Option C. -> Cost price of the painting + Amount spent for its transportation
:
C
Here, amount spent for its transportation is the overhead charge (amount spent for repairs/transportation/labour charges) which should always be added to the cost price of the item while calculating profit made on the sale.
Therefore, effective cost price isthe sum of cost price of the painting and amount spent for its transportation.

:
Marked price is same as the list price.
20% discount means that on Rs 100 (MP), the discount is Rs 20.
By unitary method, on Re 1 the discount will be Rs $\frac{20}{100}$
On Rs 220, discount = Rs $\frac{20}{100}$x 220 = Rs 44
The sale price = (Rs 220 - Rs 44) or Rs 176
OR
A discount of 20% means forMP of Rs 100, the discount is Rs 20.
Hence, the sale price is Rs 80.
Using unitary method, when MP is Rs 100, sale price is Rs 80;
When MP is Re 1, sale price is Rs $\frac{80}{100}$
Hence, when MP is Rs 220, sale price = Rs $\frac{80}{100}$ x 220 = Rs 176.

Answer: Option D. -> 3313%
:
D
Let the printed price of the article be $x$.
$\text{GST}=7\%\text{of}x=\left(\frac{7}{100}\right)\times x=\frac{7x}{100}$
$\text{Selling price}=x+\frac{7x}{100}=\frac{107x}{100}$
As per question, $\frac{107x}{100}=₹856$
$\Rightarrow x=\frac{856\times 100}{107}=₹800$
Hence, $\text{printed price}=₹800$
Discount = 30% of ₹ 800 $=\left(\frac{30}{100}\right)\times 800=₹240$
$\text{Cost price of the article}=800-240=₹560$
$\text{Overhead}=\text{cost of transportation}=₹40$
$\text{Actual cost price}=560+40=₹600$
GST is charged by the government on the sale of an item. It is collected by the shopkeeper from the customer and given to the government. Hence, while calculating profit we will not include GST amount.
$\text{Profit}=\text{Printed price}-\text{Actual cost price}=800-600=₹200.$
$\text{Profit \%}=\left(\frac{\text{profit}}{\text{cost price}}\right)\times 100=\left(\frac{200}{600}\right)\times 100$
$=\frac{100}{3}\%=33\frac{1}{3}\%$

Answer: Option C. -> ₹14080
:
C
Principal = ₹$12800,$ Rate $=10\%$
Interest for one year $=\frac{P\times r\times t}{100}=\frac{(12800\times 10\times 1)}{100}=₹1280$
So, sum due after one year $=12800+1280=₹14080$

Answer: Option C. -> 3 hours ago
:
C

If there are 1000 bacteria now, 1 hour ago there would have been 500 since the number of bacteria doubles every hour. 2 hours ago there would have been half of 500 bacteria, that is 250 bacteria. 3 hours ago there would have been 125 bacteria.