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8th Grade > Mathematics

COMPARING QUANTITIES MCQs

Total Questions : 59 | Page 4 of 6 pages
Question 31.


A man invests 5000 at a certain rate of interest, compounded annually. At the end of one year, it amounts to 5600. The rate of interest per annum is 


___ %.
 Discuss Question
Answer: Option A. ->
:

Since the tenure is 1 year,  the compound interest will be same as simple interest.
Amount = Principal + Interest
Interest = 5600 - 5000 = 600
Interest for one year =PRT100=600


R=100×6005000×1=12%


Question 32.


A table marked at ₹15000 is available for ₹14400. What is the discount %?


  1.     4%
  2.     10%
  3.     40%
  4.     60%
 Discuss Question
Answer: Option A. -> 4%
:
A

Discount %=Marked priceSelling priceMarked price×100
                     =150001440015000×100=4%


Question 33.


There are 6 apples and 6 oranges. Three more apples should be added so that the ratio of apples to oranges becomes 3 : 2.


There Are 6 Apples And 6 Oranges. Three More Apples Should ...


  1.     True
  2.     False
  3.     30.5%
  4.     32%
 Discuss Question
Answer: Option A. -> True
:
A

There are 6 apples and 6 oranges.


The ratio is 66, that is 1:1.


Let the number of apples added be x.
Then, 6+x6=32
6+x=32×6
x=96
x=3

Hence, 3 apples should be added.
Thus, the given statement is true.


Question 34.


Ravi has purchased a vehicle at ₹ 60,000. He sold it at a price 30% less than its value to Amit. Amit spent 5% of the amount he purchased in repairs. Find the percentage decrease of the price of the vehicle, including the repair price also.


  1.     30%
  2.     26.5%
  3.     30.5%
  4.     32%
 Discuss Question
Answer: Option B. -> 26.5%
:
B
Amount at which Ravi sold the vehicle =60,000(60,000×30100)=42,000
Amount spent by Amit on repairs = 42,000×5100= 2,100
Total amount spent by Amit =42,000+2,100=44,100
Decrease in price of vehicle =60,00044,100=15,900
Percentage decrease =1590060000×100=26.5%
Question 35.


The compound interest on a certain sum of money at 5% per annum for two years is ₹246. Calculate the simple interest on the same sum for three years at 6% per annum.


  1.     ₹430
  2.     ₹432
  3.     ₹442
  4.     ₹452  
 Discuss Question
Answer: Option B. -> 432
:
B

We know that, C.I=P[(1+r100)n1]where P is the principal, r is the rateof interest and t is the time period.
Hence, 246=P[(1+5100)21]


246=P[(2120)×(2120)1]246=P×(41400)


P=246×40041= 2400


Now, P=  2400,r=6% per annum and t = 3 years 


S.I=P×r×t100=2400×6×3100=432


Question 36.


I bought a second-hand car for ₹50,000, had it transported for ₹5,000 and sold it for ₹59,400. What is my profit %?


  1.     1%
  2.     0%
  3.     3%
  4.     8%
 Discuss Question
Answer: Option D. -> 8%
:
D
Profit is the difference between the selling price and total cost price 
Total cost price = Cost price + Transportation costs = ₹50,000 + ₹5,000 = ₹55,000
 Selling price = ₹59,400
Profit = ₹59400 - ₹55000 = ₹4400
Profit%=ProfitNet expenses×100
=440055000×100=8%.
Question 37.


What is the value of 200% of 12?


  1.     24
  2.     20
  3.     6
  4.     16
 Discuss Question
Answer: Option A. -> 24
:
A

200% of 12 


=200100×12=2×12=24


Question 38.


The cost of a car depreciates at the rate of 20% every year. If its present worth  is ₹ 315600, find the purchase value of the car, if it was purchased two years back.


  1.     ₹ 4,93,125
  2.     ₹ 2,01,984
  3.     ₹ 4,10884
  4.     ₹ 2,22,884
 Discuss Question
Answer: Option A. -> ₹ 4,93,125
:
A

Given that A = ₹ 3,15,600 , r = 20 % ; n = 2 years.
 
Let P be the value of the car two years ago. 
 A=P(120100)2
315600=P(115)2
315600=P(4×45×5)
P=315600×5×54×4
P= 4,93,125
Purchase value of the car= 4,93,125
 


Question 39.


On what is Goods and Service Tax (GST) levied?


  1.     Cost Price
  2.     Selling Price
  3.     Marked Price
  4.     Discount
 Discuss Question
Answer: Option B. -> Selling Price
:
B

Goods and Service Tax (GST) is levied on selling price.


Question 40.


The cost of Maruti 800 in the year 1998 was ₹ 2,50,000. After the end of one year and four months, the price underwent depreciation by 10% per annum. Its new price is


  1.     ₹ 2,25,000
  2.     ₹ 2,17,500
  3.     ₹ 2,40,000
  4.     ₹ 2,23,000
 Discuss Question
Answer: Option B. -> ₹ 2,17,500
:
B

Depreciation means a decrease in the value due to use and age of the item.


A=P×[1r100]n, where A is the amount, P is the principal, r is the rate of interest and n is the time period.


So, price at the end of one year =2,50,000×[110100]1₹ 2,25,000


Depreciation for next four months =2,25,000×10×1100×3 = ₹ 7500


So, the depreciated value after one year and four months =2,25,0007,500 =  2,17,500


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