8th Grade > Mathematics
COMPARING QUANTITIES MCQs
:
A
8% of 150=8100×150=Rs. 12
New price =150+12=Rs. 162
:
C
Principal = ₹ 12800, Rate =10%
Interest for one year =P × r × t100=(12800 × 10 × 1)100=₹ 1280
So, sum due after one year =12800+1280=₹14080
:
Marked price is same as the list price.
20% discount means that on Rs 100 (MP), the discount is Rs 20.
By unitary method, on Re 1 the discount will be Rs 20100
On Rs 220, discount = Rs 20100 x 220 = Rs 44
The sale price = (Rs 220 - Rs 44) or Rs 176
OR
A discount of 20% means for MP of Rs 100, the discount is Rs 20.
Hence, the sale price is Rs 80.
Using unitary method, when MP is Rs 100, sale price is Rs 80;
When MP is Re 1, sale price is Rs 80100
Hence, when MP is Rs 220, sale price = Rs 80100 x 220 = Rs 176.
:
D
Let the strength of the class be x.
Given that 60% are girls, so 40% are boys.
Now, 40%×x=20
(Since number of boys in the class is 20)
⇒40100×x=20
⇒x=20×10040
⇒x=50
Therefore, total number of students in the class is 50.
:
B
Let the number to be added be x, then (2+x):(3+x)=4:5
⇒2+x3+x=45⇒5(2+x)=4(3+x)⇒10+5x=12+4x⇒5x−4x=12−10⇒x=2
:
C
Here, amount spent for its transportation is the overhead charge (amount spent for repairs/transportation/labour charges) which should always be added to the cost price of the item while calculating profit made on the sale.
Therefore, effective cost price is the sum of cost price of the painting and amount spent for its transportation.
:
C
Given that, principal, P=₹15000 and time period, n=2 years .
Let the rate of interest per annum be r.
Simple interest in 2 years
S.I=15000×r×2100
⇒S.I=300r
Compound interest C.I=A−P=15000(1+r100)2−15000, here, A is the amount.
Given that C.I−S.I=96
(Since C.I > S.I)
⇒15000(1+r100)2−15000−300r=96
⇒15000(1+r100)2−300r=15096
⇒15000(1+r210000+2r100)−300r=15096
⇒15000+15r210+300r−300r=15096
⇒15r210=96
⇒15r2=960
⇒r2=64
⇒r=±8
∵ Rate of interest cannot be negative, so r=8%
:
D
Let the printed price of the article be x.
GST=7% of x=(7100)×x= 7x100
Selling price=x+7x100= 107x100
As per question, 107x100=₹ 856
⇒x=856×100107=₹ 800
Hence, printed price =₹ 800
Discount = 30% of ₹ 800 =(30100)×800=₹ 240
Cost price of the article=800−240=₹ 560
Overhead=cost of transportation =₹ 40
Actual cost price=560+40=₹ 600
GST is charged by the government on the sale of an item. It is collected by the shopkeeper from the customer and given to the government. Hence, while calculating profit we will not include GST amount.
Profit=Printed price−Actual cost price =800−600=₹200.
Profit %=(profitcost price)×100 =(200600)×100
=1003% =3313%
:
A
Let the present value of the car be V which is ₹ 35600,
Time, n=2 years, and rate of interest, r=20%
Let the purchase price be V0
Using, V=V0(1−r100)n
⇒35600=V0(1−20100)2⇒35600=V0(80100)2=V0(1625)⇒V0=35600×2516=₹ 55625