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12th Grade > Chemistry

CHEMICAL THERMODYNAMICS MCQs

Total Questions : 30 | Page 3 of 3 pages
Question 21. A well stopped thermos flask contains ice cubes. This is an example of
  1.    closed system
  2.    open system
  3.    isolated system
  4.    non-thermodynamic system
 Discuss Question
Answer: Option C. -> isolated system
:
C
There is no exchange of matter or energy from the flask.
Question 22. Two moles of an ideal gas is expanded isothermally and reversibly from 1 litre to 10 litre at 300 K. The enthalpy change ( in kJ) for the process is
  1.    11.4 kJ
  2.    −11.4 kJ
  3.    0 kJ
  4.    4.8 kJ
 Discuss Question
Answer: Option C. -> 0 kJ
:
C
H=nCpTsolution;sinceT=0
so, H=0
Question 23. An ideal gas expands in volume from 1 × 103 to 1 × 102 m3 at 300 K against a constant pressure of 1 × 105 Nm2. The work done is
  1.    270 kJ
  2.    −270 kJ
  3.    −900 J
  4.    900 kJ 
 Discuss Question
Answer: Option C. -> −900 J
:
C
w=PΔV=105(1×1021×103)
= 900J
Question 24. The dissociation energy of CH4 is 400 Kcal mol1 and that of ethane is 670 Kcal mol1. The C - C bond energy is.
  1.    270 kcal
  2.    70 kcal
  3.    200 kcal
  4.    240 kcal
 Discuss Question
Answer: Option B. -> 70 kcal
:
B
CH4 has 4 C - H bonds
Energy needed to break a single C - H bond is 4004= 100 Kcal
C2H6 has 6 C - H bonds
The C - C bond energy can be given by
​670 Kcal - 6 × 100 Kcal = 70 Kcal
Question 25. The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25C are 400 kJ/mol, 300 kJ/mol and 1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25C is
  1.    + 2900 kJ
  2.    −2900 kJ
  3.    −16.11 kJ
  4.    +16.11 kJ
 Discuss Question
Answer: Option C. -> −16.11 kJ
:
C
The standard enthalpy of the combustion of glucose can be calculated by the equ.
C6H12O6(s)+6O2(g)6CO2(g)+6H2O(l)
ΔHc=6×ΔHf(CO2)+6×ΔHf(H2O)ΔHf[C6H12O6]
ΔH0=2900180=16.11kJ/gm
Question 26. In a process a system does 140 J of work on the surrondings and only 40 J of heat is added to the system, hence change in internal energy is
  1.    180 J
  2.    -180 J
  3.    -23.92 Cal
  4.    -180 J
 Discuss Question
Answer: Option C. -> -23.92 Cal
:
C
Given W=140J;q=405
ΔE=q+W=40140=100J(1cal=4.18J)=23.92Cal
Question 27. Which of the following is /are true in the case of an adiabatic process
  1.    q = W
  2.    △U=q
  3.    q=0
  4.    None
 Discuss Question
Answer: Option C. -> q=0
:
C
For adiabatic process that remain const i.e.q0,U=W
Question 28. The enthalpies for the following reactions at 25°C are given.
12 H2(g) + 12 O2(g)OH(g); H = 10.06 K cal
H2(g)2H(g); H = 104.18 K cal
O2(g)2O(g); H = 118.32 K cal
Calculate the OH bond energy in the O - H group
  1.    100.19 K col
  2.    101.19 K col
  3.    -101.19 K col
  4.    -100.19 K col
 Discuss Question
Answer: Option C. -> -101.19 K col
:
C
H(g) + O(g) O - H(g) Required equation
Given: 12H2(g)+12O2(g)OH(g);H=+10.06Kcal
H(g)12H2(g);H=52.09Kcal
O(g)12O2(g);H=59.16Kcal
Adding them we get H(g)+O(g)+(OH)(g)H=101.19Kcal
Question 29. The heat of combustion of yellow phosphorous & red phosphorous are - 9.91 KJ and  - 8.78 KJ respectively. The heat of transition of yellow phosphorous to red phosphorous is:
  1.    - 18.69 KJ
  2.    + 1.13 KJ
  3.    + 18.69 KJ
  4.    - 1.13 KJ
 Discuss Question
Answer: Option D. -> - 1.13 KJ
:
D
The given equations for the combustions of different types of phosphorous are:
(y) P4+5O2P4O109.91KJ(i)
(R) P4+5O2P4O108.78KJ(ii)
Now when we subtract we get (i) - (ii) gives
​(y) P4(R)P41.13KJ
Question 30. The enthalpy of neutralization of HCl and NaOH is 57 kJ mol1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
  1.    57 × 34
  2.    57 × 0.5
  3.    57
  4.    57 × 0.25
 Discuss Question
Answer: Option A. -> 57 × 34
:
A
H+OHH2O+57kJmol1
nH+=2×nH2SO4=2×0.5=1.0
nOH=nNaOH=0.75
Heat evolved = 0.75×57=34×57kJ

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