Question
The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25∘C are −400 kJ/mol, −300 kJ/mol and −1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25∘C is
Answer: Option C
:
C
The standard enthalpy of the combustion of glucose can be calculated by the equ.
C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l)
ΔHc=6×ΔHf(CO2)+6×ΔHf(H2O)−ΔHf[C6H12O6]
ΔH0=−2900180=−16.11kJ/gm
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:
C
The standard enthalpy of the combustion of glucose can be calculated by the equ.
C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l)
ΔHc=6×ΔHf(CO2)+6×ΔHf(H2O)−ΔHf[C6H12O6]
ΔH0=−2900180=−16.11kJ/gm
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