Question
The enthalpies for the following reactions at 25°C are given.
12 H2(g) + 12 O2(g)→OH(g); △H = 10.06 K cal
H2(g)→2H(g); △H = 104.18 K cal
O2(g)→2O(g); △H = 118.32 K cal
Calculate the OH bond energy in the O - H group
12 H2(g) + 12 O2(g)→OH(g); △H = 10.06 K cal
H2(g)→2H(g); △H = 104.18 K cal
O2(g)→2O(g); △H = 118.32 K cal
Calculate the OH bond energy in the O - H group
Answer: Option C
:
C
H(g) + O(g) → O - H(g) Required equation
Given: 12H2(g)+12O2(g)→OH(g);△H=+10.06Kcal
H(g)→12H2(g);△H=−52.09Kcal
O(g)→12O2(g);△H=−59.16Kcal
Adding them we get H(g)+O(g)+(OH)(g)△H=−101.19Kcal
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:
C
H(g) + O(g) → O - H(g) Required equation
Given: 12H2(g)+12O2(g)→OH(g);△H=+10.06Kcal
H(g)→12H2(g);△H=−52.09Kcal
O(g)→12O2(g);△H=−59.16Kcal
Adding them we get H(g)+O(g)+(OH)(g)△H=−101.19Kcal
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