Question
In a process a system does 140 J of work on the surrondings and only 40 J of heat is added to the system, hence change in internal energy is
Answer: Option C
:
C
Given W=−140J;q=405
ΔE=q+W=40−140=−100J(1cal=4.18J)=−23.92Cal
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:
C
Given W=−140J;q=405
ΔE=q+W=40−140=−100J(1cal=4.18J)=−23.92Cal
Was this answer helpful ?
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