Reasoning Aptitude > Data Interpretation
BAR GRAPH MCQs
Bar Charts
Total Questions : 165
| Page 15 of 17 pages
Question 141. Directions (1 - 5): The cumulative bar chart below gives us the production of four Products A, B, C and D for four years. It is known that the total production increases @20% over its value in the previous year. The difference between C's production in 2003 and A's production in 2001 is 2640 units.
Production of A, B, C and D.
Which of the following is Not true?
Production of A, B, C and D.
Which of the following is Not true?
Answer: Option C. -> The only product that does not show an increasing
Statement C is not true, since both A and B have not shown an increasing trend.
Statement C is not true, since both A and B have not shown an increasing trend.
Answer: Option D. -> B
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
Clearly B travelled at the same speed on both the days.
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
Clearly B travelled at the same speed on both the days.
Answer: Option D. -> 13.8 m/s
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Speed of C on Day 2} \cr
& = 45 \text{ km/hr} \cr
& = \left(45\times\frac{5}{18}\right) \text{m/sec} \cr
& = \frac{25}{2} \text{ m/s} \cr
& = 12.5 \text{ m/s} \cr} $$
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Speed of C on Day 2} \cr
& = 45 \text{ km/hr} \cr
& = \left(45\times\frac{5}{18}\right) \text{m/sec} \cr
& = \frac{25}{2} \text{ m/s} \cr
& = 12.5 \text{ m/s} \cr} $$
Answer: Option C. -> 11 km/hr
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
Difference between the speed of A on Day 1 and speed of C on Day 1
= (63 - 52) km/hr
= 11 km/hr
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
Difference between the speed of A on Day 1 and speed of C on Day 1
= (63 - 52) km/hr
= 11 km/hr
Answer: Option C. -> 85%
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{636}{703}\times100\right)\% \cr
& = \frac{63600}{703}\% \cr
& = 90.46\% \cr
& \approx 90\% \cr} $$
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Required %} \cr
& = \left(\frac{636}{703}\times100\right)\% \cr
& = \frac{63600}{703}\% \cr
& = 90.46\% \cr
& \approx 90\% \cr} $$
Answer: Option B. -> 17 : 13
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Required ratio} \cr
& = \frac{\text{Speed of D on Day 2}}{\text{Speed of E on Day 2}} \cr
& = \frac{51}{39} \cr
& = \frac{17}{13} \cr
& = 17 : 13 \cr} $$
$$\eqalign{
& \text{Speeds of vehicles on Day 1:} \cr
& \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr
& \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr
& \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr
& \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr
& \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr
& \cr
& \text{Speed of vehicles on Day 2:} \cr
& \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr
& \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr
& \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr
& \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr
& \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr
& \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$
$$\eqalign{
& \text{Required ratio} \cr
& = \frac{\text{Speed of D on Day 2}}{\text{Speed of E on Day 2}} \cr
& = \frac{51}{39} \cr
& = \frac{17}{13} \cr
& = 17 : 13 \cr} $$
Answer: Option A. -> 24
Given $$x$$% of demand for company C = Demand for company B
$$\eqalign{
& \Rightarrow \frac{2500\times x}{100} = 600 \cr
& \Rightarrow 25x = 600 \cr
& \Rightarrow x = \frac{600}{25} \cr
& \Rightarrow x = 24 \cr} $$
Given $$x$$% of demand for company C = Demand for company B
$$\eqalign{
& \Rightarrow \frac{2500\times x}{100} = 600 \cr
& \Rightarrow 25x = 600 \cr
& \Rightarrow x = \frac{600}{25} \cr
& \Rightarrow x = 24 \cr} $$
Answer: Option B. -> 280
Total production of the five companies
= 1500 + 1800 +1000 + 2700 + 2200
= 9200
Total demand of the five companies
= 3000 + 600 + 2500 + 1200 + 3300
= 10600
∴ Required difference
$$\eqalign{
& = \frac{1}{5}\left(10600-9200\right) \cr
& = \frac{1}{5}\times1400 \cr
& = 280 \cr} $$
Total production of the five companies
= 1500 + 1800 +1000 + 2700 + 2200
= 9200
Total demand of the five companies
= 3000 + 600 + 2500 + 1200 + 3300
= 10600
∴ Required difference
$$\eqalign{
& = \frac{1}{5}\left(10600-9200\right) \cr
& = \frac{1}{5}\times1400 \cr
& = 280 \cr} $$
Answer: Option D. -> 1.8
Production of company D = 2700
Production of company A = 1500
$$\eqalign{
& h = \frac{\text{Production of company D}}{\text{Production of company A}} \cr
& h = \frac{2700}{1500} \cr
& h = \frac{9}{5} \cr
& h = 1.8 \cr} $$
Production of company D = 2700
Production of company A = 1500
$$\eqalign{
& h = \frac{\text{Production of company D}}{\text{Production of company A}} \cr
& h = \frac{2700}{1500} \cr
& h = \frac{9}{5} \cr
& h = 1.8 \cr} $$
Answer: Option D. -> B
Difference between demand and production of company A
= 3000 - 1500
= 1500
Difference between production and demand of company D
= 2700 - 1200
= 1500
Difference between demand and production of company A
= 3000 - 1500
= 1500
Difference between production and demand of company D
= 2700 - 1200
= 1500