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Quantitative Aptitude

AGES MCQs

Problems On Ages

Total Questions : 432 | Page 38 of 44 pages
Question 371. The sum of the ages of a daughter and her mother is 56 years. After 4 years, the age of the mother will be three times that of the daughter. At present their ages are ?
  1.    10 years, 46 years
  2.    12 years, 44 years
  3.    11 years, 45 years
  4.    13 years, 43 years
 Discuss Question
Answer: Option B. -> 12 years, 44 years
Let daughter's age be $$x$$ years.
Then, mother's age = (56 $$-\, x\,$$) years
$$\eqalign{
& \left( {56 - x} \right)+4 = 3\left( {x + 4} \right) \cr
& \Rightarrow 60 - x = 3x + 12 \cr
& \Rightarrow 4x = 48 \cr
& \Rightarrow x = 12 \cr} $$
∴ Daughter's age = 12 years
And the mother's age = (56 $$-$$ 12) = 44 years
Question 372. The present age of son is half of the present age of his mother. Ten years ago, his mother's age was thrice the age of her son. What is the present age of the son ?
  1.    20 years
  2.    25 years
  3.    30 years
  4.    40 years
 Discuss Question
Answer: Option A. -> 20 years
Let mother's age be 2x years, Then, son's age = x years
$$\eqalign{
& \therefore \left( {2x - 10} \right) = 3\left( {x - 10} \right) \cr
& \Rightarrow 2x - 10 = 3x - 30 \cr
& \Rightarrow x = 20 \cr} $$
Son's age = 20 years
Question 373. Rajan got married 8 years ago. His present age is $$\frac{6}{5}$$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marrige. The age of Rajan's sister is = ?
  1.    32 years
  2.    36 years
  3.    38 years
  4.    40 years
 Discuss Question
Answer: Option C. -> 38 years
Let Rajan's age 8 years ago be x years, Then, present age = (x + 8) years
$$\eqalign{
& \therefore x + 8 = \frac{6}{5}x \cr
& \Rightarrow 5x + 40 = 6x \cr
& \Rightarrow x = 40 \cr} $$
Rajan's sister's age 8 years ago = (40 - 10) years = 30 years
∴ His sister's age now = (30+8) years = 38 years
Question 374. Reenu's father was 38 years of age when she was born while her mother was 36 years old when her brother 4 years younger to her was born. What is the difference between the ages of her parents ?
  1.    2 years
  2.    4 years
  3.    6 years
  4.    8 years
  5.    None of these
 Discuss Question
Answer: Option C. -> 6 years
Mother's age when Reenu's brother was born = 36 year
Father's age when Reenu's brother was born = (38 + 4) years = 42 year
Required difference = (42 - 36) years = 6 years
Question 375. A couple has a son and a daughter. The age of the father is four times that of the son and the age of the daughter is one-third of that of her mother. The wife is 6 years younger to her husband and the sister is 3 years older then her brother. The mother's age is = ?
  1.    42 years
  2.    48 years
  3.    54 years
  4.    63 years
 Discuss Question
Answer: Option C. -> 54 years
M → Mother, F → Father, S → Son and D → Daughter
F = 4S, D = $$\frac{1}{3}$$M, M = F - 6 and S = D - 3
$$\eqalign{
& \therefore M = 3D = 3\left( {S + 3} \right) \cr
& = 3S + 9 = \frac{3}{4}F + 9 = \frac{3}{4}\left( {M + 6} \right) + 9 \cr
& = \frac{3}{4}M + \frac{3}{4} \times 6 + 9 \cr
& \Rightarrow \left( {M - \frac{3}{4}M} \right) = \left( {\frac{9}{2} + 9} \right) \cr
& \Rightarrow \frac{1}{4}M = \frac{{27}}{2} \cr
& \Rightarrow M = \left( {\frac{{27}}{2} \times 4} \right) \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 54\,{\text{years}} \cr
& \therefore {\text{ The mother is 54 years old}}{\text{.}} \cr} $$
Question 376. A man was asked to state his age in years. His reply was, "Take my age 3 years hence, multiply it by 3 and then subtract 3 times my age 3 years ago and you will know how old I am". What is the age of the man ?
  1.    18 years
  2.    20 years
  3.    24 years
  4.    32 years
 Discuss Question
Answer: Option A. -> 18 years
Let the present age of the man be x years
Then,
$$\eqalign{
& \Rightarrow {\text{3}}\left( {x + 3} \right) - 3\left( {x - 3} \right) = x \cr
& \Rightarrow \left( {3x + 9} \right) - \left( {3x - 9} \right) = x \cr
& \Rightarrow x = 18 \cr} $$
∴ The present age of the man is 18 years
Question 377. The ratio of a man's age and his son's age is 7 : 3 and the product of their ages is 756. The ratio of their ages after 6 years will be ?
  1.    5 : 2
  2.    2 : 1
  3.    11 : 7
  4.    13 : 9
  5.    None of these
 Discuss Question
Answer: Option B. -> 2 : 1
Let the man's age be 7x years , Then son's age = 3x years
$$\eqalign{
& \therefore {\text{7}}x \times 3x = 756 \cr
& \Rightarrow 21{x^2} = 756 \cr
& \Rightarrow {x^2} = 756 \cr
& \Rightarrow {x^2} = 36 \cr
& \Rightarrow x = 6 \cr} $$
The ratio of their ages after 6 years
$$\eqalign{
& {\text{ = }}\left( {7x + 6} \right):\left( {3x + 6} \right) \cr
& = \left( {7 \times 6 + 6} \right):\left( {3 \times 6 + 6} \right) \cr
& = 48:24 \cr
& = 2:1 \cr} $$
Question 378. Rahul is as much younger than Sagar as he is older than Purav. If the sum of the ages of Purav and Sagar is 66 years, and Sagar's age is 48 years, then what is the difference between Rahul and Purav's age ? ( in years)
  1.    18
  2.    15
  3.    16
  4.    20
  5.    Cannot be determined
 Discuss Question
Answer: Option B. -> 15
Let the age of Rahul, Sagar and Purav be x, y and z respectively
According to the given information
Age of Sagar - Age of Rahul = Age of Rahul - Age of Purav
$$\eqalign{
& \Rightarrow y - x = x - z \cr
& \Rightarrow 2x = y + z......(i) \cr} $$
Also y + z = 66 years
From (i) x = 33 years
Also as per equation (i) we have Purav's age + Sagar age = 66 years
by going through option (A) given Purav = 18, and Rahul = 33 years, Sagar = 48 years
Difference between Rahul's and Purav's age = 33 - 18 = 15 years
Question 379. The sum of present ages of a father and his son is 8 years more than the present age of the mother. The mother is 22 years older than the son. What will be the age of the father after 4 years?
  1.    34 years
  2.    36 years
  3.    40 years
  4.    38 years
  5.    28 years
 Discuss Question
Answer: Option A. -> 34 years
Let present age of father , mother and son be x, y and z respectively
Sum of present ages of father and son = (Mother's present age + 8 years)
x + z = y + 8 years.................(i)
Mother's present age = Son's present age + 22 years)
⇒ y = z + 22 years..............(ii)
Put the value of y in equation (i) we get
x + z = z + 22 + 8
x + z = z + 30
x = 30 years
∴ Father's present age = 30 years
Age of father after four years = 30 + 4 = 34 years
∴ Required age of father = 34 years
Question 380. Ten years hence, the respective ratio between Simmi's age ans Niti's age will be 7 : 9. Two years ago, the respective ratio between Simmi's and Niti's age was 1 : 3. If Abhay is 4 years older then Niti, what is Abhay's present age ? (in years)
  1.    8
  2.    4
  3.    16
  4.    12
  5.    20
 Discuss Question
Answer: Option D. -> 12
Let present ages of Simmi and Niti be a and b years respectively.
Ten years hence, the ratio between Simmi's age and Niti's age = 7 : 9
According to question
$$\frac{{a + 10}}{{b + 10}} = \frac{7}{9}$$
By cross multiplying we get
$$\eqalign{
& \Rightarrow 9a + 90 = 7b + 70 \cr
& \Rightarrow 7b - 9a = 20......(i) \cr
& {\text{Also}},\frac{{a - 2}}{{b - 2}} = \frac{1}{3} \cr} $$
By cross multiplying we get
$$\eqalign{
& \Rightarrow 3a - 6 = b - 2 \cr
& \Rightarrow 3a - b = 4.....(ii) \cr} $$
Multiplying equation (ii) by 3
$$9a - 3b = 12.....(iii)$$
Adding equation (ii) and (iii) we get
$$\eqalign{
& - 9a + 7b = 20 \cr
& 4b = 32 \cr
& b = 8{\text{ year}} \cr} $$
From equation (ii) we get
$$\eqalign{
& a = \frac{{4 + b}}{3} \cr
& \,\,\,\,\, = \frac{{4 + 8}}{3} \cr
& \,\,\,\,\,\, = \frac{{12}}{3} \cr
& \,\,\,\,\,\, = 4\,{\text{year}} \cr} $$
Since, Abhay is 4 years older to Niti
So, Abhay's present age = 8 + 4 = 12 years

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