Quantitative Aptitude
AGES MCQs
Problems On Ages
Total Questions : 432
| Page 36 of 44 pages
Answer: Option C. -> 6 years
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 - 36) years = 6 years.
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 - 36) years = 6 years.
Answer: Option B. -> 7 : 3
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
Answer: Option A. -> 16 years
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years Then,
$$\eqalign{
& \frac{{\left( {6x + 6} \right) + 4}}{{\left( {5x + 6} \right) + 4}} = \frac{{11}}{{10}} \cr
& \Rightarrow \frac{{6x + 10}}{{5x + 10}} = \frac{{11}}{{10}} \cr
& \Rightarrow 10\left( {6x + 10} \right) = 11\left( {5x + 10} \right) \cr
& \Rightarrow 60x + 100 = 55x + 100 \cr
& \Rightarrow 5x = 10 \cr
& \Rightarrow x = 2 \cr} $$
Sagar's present age = (5x + 6) years = (5 × 2 + 6) years = 16 years
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years Then,
$$\eqalign{
& \frac{{\left( {6x + 6} \right) + 4}}{{\left( {5x + 6} \right) + 4}} = \frac{{11}}{{10}} \cr
& \Rightarrow \frac{{6x + 10}}{{5x + 10}} = \frac{{11}}{{10}} \cr
& \Rightarrow 10\left( {6x + 10} \right) = 11\left( {5x + 10} \right) \cr
& \Rightarrow 60x + 100 = 55x + 100 \cr
& \Rightarrow 5x = 10 \cr
& \Rightarrow x = 2 \cr} $$
Sagar's present age = (5x + 6) years = (5 × 2 + 6) years = 16 years
Answer: Option A. -> $${\text{6}}\frac{2}{3}{\text{ }}$$ years
Vimal's present age = (8 + 2) years = 10 years
Sneh's father's age = 2(10 + 10) years = 40 years
Sneh's age
$$\eqalign{
& {\text{ = }}\left( {\frac{1}{6} \times 40} \right){\text{ years }} \cr
& {\text{ = }}\frac{{20}}{3}{\text{years }} \cr
& {\text{ = 6}}\frac{2}{3}{\text{years}} \cr} $$
Vimal's present age = (8 + 2) years = 10 years
Sneh's father's age = 2(10 + 10) years = 40 years
Sneh's age
$$\eqalign{
& {\text{ = }}\left( {\frac{1}{6} \times 40} \right){\text{ years }} \cr
& {\text{ = }}\frac{{20}}{3}{\text{years }} \cr
& {\text{ = 6}}\frac{2}{3}{\text{years}} \cr} $$
Question 355. Eight year ago, Poorvi's age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7 : 6. If Poorvi's husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter ? (in year)
Answer: Option B. -> 23 years
Let the age of the son and the daughter of Poorvi be 6a years and 7a years respectively.
5 years hence, present age of son = 6a - 5 and present age of daughter = 7a - 5
According to the question,
Eight years ago, the age of Poorvi = 6a - 5 + 7a - 5 = 13a - 10
So, present age of Poorvi = 13a - 10 + 8 = 13a - 2
Since, present age of Poorvi husband = 3 (6a - 5)
The difference of present age of Poorvi husband and Poorvi = 7 (Given)
$$\eqalign{
& {\text{3}}\left( {6a - 5} \right) - \left( {13a - 2} \right) = 7 \cr
& \Rightarrow 18a - 15 - 13a + 2 = 7 \cr
& \Rightarrow 5a = 20 \cr
& \Rightarrow a = 4 \cr} $$
The present age of daughter
= (7a - 5)
= 7 × 4 - 5
= 23 years
Let the age of the son and the daughter of Poorvi be 6a years and 7a years respectively.
5 years hence, present age of son = 6a - 5 and present age of daughter = 7a - 5
According to the question,
Eight years ago, the age of Poorvi = 6a - 5 + 7a - 5 = 13a - 10
So, present age of Poorvi = 13a - 10 + 8 = 13a - 2
Since, present age of Poorvi husband = 3 (6a - 5)
The difference of present age of Poorvi husband and Poorvi = 7 (Given)
$$\eqalign{
& {\text{3}}\left( {6a - 5} \right) - \left( {13a - 2} \right) = 7 \cr
& \Rightarrow 18a - 15 - 13a + 2 = 7 \cr
& \Rightarrow 5a = 20 \cr
& \Rightarrow a = 4 \cr} $$
The present age of daughter
= (7a - 5)
= 7 × 4 - 5
= 23 years
Answer: Option D. -> 18 years
Let the present age of Y be a years
Three years ago X's age = 3a years
Then, present age of X is (3a + 3)
Z's present age = 2a
According to question
Now, (3a + 3) - 2a = 12
a = 9 year
∴ Present age of Z = 2a = 2 × 9 = 18 years
Let the present age of Y be a years
Three years ago X's age = 3a years
Then, present age of X is (3a + 3)
Z's present age = 2a
According to question
Now, (3a + 3) - 2a = 12
a = 9 year
∴ Present age of Z = 2a = 2 × 9 = 18 years
Answer: Option B. -> 5 years
Let Sulekha age be 9 year,Then Arunima's age = 8x years
$$\eqalign{
& \frac{{9x + 5}}{{8x + 5}} = \frac{{10}}{9} \cr
& \Rightarrow 9\left( {9x + 5} \right) = 10\left( {8x + 5} \right) \cr
& \Rightarrow 81x + 45 = 80x + 50 \cr
& \Rightarrow x = 5 \cr} $$
Difference in their ages = (9x - 8x) years = x years = 5 years
Let Sulekha age be 9 year,Then Arunima's age = 8x years
$$\eqalign{
& \frac{{9x + 5}}{{8x + 5}} = \frac{{10}}{9} \cr
& \Rightarrow 9\left( {9x + 5} \right) = 10\left( {8x + 5} \right) \cr
& \Rightarrow 81x + 45 = 80x + 50 \cr
& \Rightarrow x = 5 \cr} $$
Difference in their ages = (9x - 8x) years = x years = 5 years
Answer: Option B. -> 8 : 7
$$\eqalign{
& {\text{A's age = }}\left( {44 \times \frac{6}{{11}}} \right){\text{years}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 24 years}} \cr
& {\text{And B's age = }}\left( {44 - 24} \right){\text{years}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 20 years}} \cr} $$
Ratio of their ages after 8 years
$$\eqalign{
& {\text{ = }}\frac{{\left( {24 + 8} \right)}}{{\left( {20 + 8} \right)}} \cr
& = \frac{{32}}{{28}} \cr
& = \frac{8}{7} \cr
& = 8:7 \cr} $$
$$\eqalign{
& {\text{A's age = }}\left( {44 \times \frac{6}{{11}}} \right){\text{years}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 24 years}} \cr
& {\text{And B's age = }}\left( {44 - 24} \right){\text{years}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 20 years}} \cr} $$
Ratio of their ages after 8 years
$$\eqalign{
& {\text{ = }}\frac{{\left( {24 + 8} \right)}}{{\left( {20 + 8} \right)}} \cr
& = \frac{{32}}{{28}} \cr
& = \frac{8}{7} \cr
& = 8:7 \cr} $$
Answer: Option A. -> 3 Years
Let Nishi's age be 6x years,
Then Vinnee's age = 5x years
$$\eqalign{
& \therefore \frac{{6x + 9}}{{5x + 9}} = \frac{9}{8} \cr
& \Rightarrow 8\left( {6x + 9} \right) = 9\left( {5x + 9} \right) \cr
& \Rightarrow 48x - 45x = 81 - 72 \cr
& \Rightarrow 3x = 9 \cr
& \Rightarrow x = 3 \cr
& {\text{Difference in their ages}} \cr
& {\text{ = }}\left( {6x - 5x} \right) \cr
& = x {\text{ years}} \cr
& = {\text{3 years}} \cr} $$
Let Nishi's age be 6x years,
Then Vinnee's age = 5x years
$$\eqalign{
& \therefore \frac{{6x + 9}}{{5x + 9}} = \frac{9}{8} \cr
& \Rightarrow 8\left( {6x + 9} \right) = 9\left( {5x + 9} \right) \cr
& \Rightarrow 48x - 45x = 81 - 72 \cr
& \Rightarrow 3x = 9 \cr
& \Rightarrow x = 3 \cr
& {\text{Difference in their ages}} \cr
& {\text{ = }}\left( {6x - 5x} \right) \cr
& = x {\text{ years}} \cr
& = {\text{3 years}} \cr} $$
Answer: Option A. -> 2 Years
Let Shakti's age be 8$$x$$ years,
Then Kanti's age = 7$$x$$ years
$$\eqalign{
& \therefore \frac{{8x + 10}}{{7x + 10}} = \frac{{13}}{{12}} \cr
& \Rightarrow 12\left( {8x + 10} \right) = 13\left( {7x + 10} \right) \cr
& \Rightarrow 96x + 120 = 91x + 130 \cr
& \Rightarrow 5x = 10 \cr
& \Rightarrow x = 2 \cr} $$
Difference between their ages
$$\eqalign{
& = \left( {8x - 7x} \right) \cr
& = {\text{ }}x\,{\text{years}} \cr
& {\text{ = 2}}\,{\text{years}} \cr} $$
Let Shakti's age be 8$$x$$ years,
Then Kanti's age = 7$$x$$ years
$$\eqalign{
& \therefore \frac{{8x + 10}}{{7x + 10}} = \frac{{13}}{{12}} \cr
& \Rightarrow 12\left( {8x + 10} \right) = 13\left( {7x + 10} \right) \cr
& \Rightarrow 96x + 120 = 91x + 130 \cr
& \Rightarrow 5x = 10 \cr
& \Rightarrow x = 2 \cr} $$
Difference between their ages
$$\eqalign{
& = \left( {8x - 7x} \right) \cr
& = {\text{ }}x\,{\text{years}} \cr
& {\text{ = 2}}\,{\text{years}} \cr} $$