Question
Rajan got married 8 years ago. His present age is $$\frac{6}{5}$$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marrige. The age of Rajan's sister is = ?
Answer: Option C
Let Rajan's age 8 years ago be x years, Then, present age = (x + 8) years
$$\eqalign{
& \therefore x + 8 = \frac{6}{5}x \cr
& \Rightarrow 5x + 40 = 6x \cr
& \Rightarrow x = 40 \cr} $$
Rajan's sister's age 8 years ago = (40 - 10) years = 30 years
∴ His sister's age now = (30+8) years = 38 years
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Let Rajan's age 8 years ago be x years, Then, present age = (x + 8) years
$$\eqalign{
& \therefore x + 8 = \frac{6}{5}x \cr
& \Rightarrow 5x + 40 = 6x \cr
& \Rightarrow x = 40 \cr} $$
Rajan's sister's age 8 years ago = (40 - 10) years = 30 years
∴ His sister's age now = (30+8) years = 38 years
Was this answer helpful ?
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