Question
The sum of present ages of a father and his son is 8 years more than the present age of the mother. The mother is 22 years older than the son. What will be the age of the father after 4 years?
Answer: Option A
Let present age of father , mother and son be x, y and z respectively
Sum of present ages of father and son = (Mother's present age + 8 years)
x + z = y + 8 years.................(i)
Mother's present age = Son's present age + 22 years)
⇒ y = z + 22 years..............(ii)
Put the value of y in equation (i) we get
x + z = z + 22 + 8
x + z = z + 30
x = 30 years
∴ Father's present age = 30 years
Age of father after four years = 30 + 4 = 34 years
∴ Required age of father = 34 years
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Let present age of father , mother and son be x, y and z respectively
Sum of present ages of father and son = (Mother's present age + 8 years)
x + z = y + 8 years.................(i)
Mother's present age = Son's present age + 22 years)
⇒ y = z + 22 years..............(ii)
Put the value of y in equation (i) we get
x + z = z + 22 + 8
x + z = z + 30
x = 30 years
∴ Father's present age = 30 years
Age of father after four years = 30 + 4 = 34 years
∴ Required age of father = 34 years
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