Question
Two waves, each having a frequency of 100 Hz and a wavelength of 2.0 cm, are travelling in the same direction on a string. What is the phase difference between the waves (a) if the second wave was produced 0.015 s later than the first one at the same place, what would be the resultant amplitude? [Given individual amplitudes = 2.0 mm]
Answer: Option D
:
D
Phase diagram method can be used here but for that we need to calculate the phase difference.
Δϕ=2πΔtT
Here Δt=0.015s
T1 which is the time period =1f
T=1100
So Δϕ=2π0.0151100=3π=2π+π as 2π is the period, the effective phase difference is π now let's draw
the phase diagram
So we can see that net amplitude would be zero.
Was this answer helpful ?
:
D
Phase diagram method can be used here but for that we need to calculate the phase difference.
Δϕ=2πΔtT
Here Δt=0.015s
T1 which is the time period =1f
T=1100
So Δϕ=2π0.0151100=3π=2π+π as 2π is the period, the effective phase difference is π now let's draw
the phase diagram
So we can see that net amplitude would be zero.
Was this answer helpful ?
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