Question
A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled and the wire radius halved, the electrical power dissipated would be
Answer: Option B
:
B
Power P=e2R; hence e=−(dϕdt) where ϕ =NBA
∴e=−NA(dbdt) Also R∝1r2
Where R = resistance, r = radius, l =Length
∴P∝N2r2l⇒P1P2=1
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:
B
Power P=e2R; hence e=−(dϕdt) where ϕ =NBA
∴e=−NA(dbdt) Also R∝1r2
Where R = resistance, r = radius, l =Length
∴P∝N2r2l⇒P1P2=1
Was this answer helpful ?
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