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Question
What is the equation of a sinusoidal wave moving in the positive x direction with wave length 6 m and time period 0.5s. The amplitude of the wave is 5 m.
Options:
A .  y=6sin(2π5x−4πt)
B .  y=5sin(π3x−4πt)
C .  y=5sin(x−t)
D .  None of these
Answer: Option B
:
B
here λ=6m
k=2π6=π3
ω=2πT=2π0.5=4π
given,amplitude =5m
y=5sin(π3x4πt)
[the standard equation is y=Asin(kx-ω t)]

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