In series with 20 ohm resistor a 5 henry inductor is placed. To the combination

Question

In series with 20 ohm resistor a 5 henry inductor is placed. To the combination an e.m.f. of 5 volt is applied. What will be the rate of increase of current at t = 0.25 sec

Options:

A . e

B . e−2

C . e−1

D . None of these

Answer: Option C
:
C

i = i_{o} (1 - e^{- \frac{R t}{L}}) \Rightarrow \frac{d i}{d t} = i_{o} (\frac{R}{L}) e^{\frac{R t}{L}} = \frac{E}{L} e^{\frac{R t}{L}}

On putting values

\frac{d i}{d t} = \frac{1}{e} = e^{- 1} .

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