Question
Two Charges Q1 and Q2 are as shown in the figure. A third charge Q3 is moved from points A to B along a circular path. Change in potential energy of the system is
Answer: Option C
:
C
ΔU=Uf−UiUf=k[Q1Q20.6+Q2Q30.2+Q3Q10.8]ΔU=Uf−Ui=kQ2Q3[10.2−1]=4kQ2Q3
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:
C
ΔU=Uf−UiUf=k[Q1Q20.6+Q2Q30.2+Q3Q10.8]ΔU=Uf−Ui=kQ2Q3[10.2−1]=4kQ2Q3
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