Question
Three particles, each of charge 10 μC are placed at the corners of an equilateral triangle of side 10 cm. The electrostatic potential energy of the system is
Given (14πϵ=9×109 N−m2/C2)
Given (14πϵ=9×109 N−m2/C2)
Answer: Option C
:
C
For pair of charge U=14πϵ0[10×10−6×10×10−610100+10×10−6×10×10−610100+10×10−6×10×10−610100]
=3×9×109×100×10−12×10010=27J
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C
For pair of charge U=14πϵ0[10×10−6×10×10−610100+10×10−6×10×10−610100+10×10−6×10×10−610100]
=3×9×109×100×10−12×10010=27J
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